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5n^2-n=13
We move all terms to the left:
5n^2-n-(13)=0
We add all the numbers together, and all the variables
5n^2-1n-13=0
a = 5; b = -1; c = -13;
Δ = b2-4ac
Δ = -12-4·5·(-13)
Δ = 261
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{261}=\sqrt{9*29}=\sqrt{9}*\sqrt{29}=3\sqrt{29}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3\sqrt{29}}{2*5}=\frac{1-3\sqrt{29}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3\sqrt{29}}{2*5}=\frac{1+3\sqrt{29}}{10} $
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